Altanis

1.5Holomorphic Functions

Updated 2 Aug 2026Chapter (PDF)

[1.5.1]Definition(Holomorphicity)#

Suppose ΩC\Omega \subseteq \bC is an open set with z0Ωz_0 \in \Omega. Then a function ff is said to be holomorphic at z0z_0 if the value

f(z0)=limh0f(z0+h)f(z0)hhCf'(z_0) = \lim_{h \to 0} \frac{f(z_0 + h) - f(z_0)}{h} \quad h \in \bC

exists.

A function ff is said to be holomorphic on Ω\Omega if it is holomorphic at every point in Ω\Omega. For a general, non-open set CCC \subseteq \bC, we say ff is holomorphic on CC if it is holomorphic on some open set containing CC.

Note that every point in an open set is an interior point, and so the open diskDr(z0)ΩD_r(z_0) \subseteq \Omega for some small r>0r > 0 (ensuring z0+hΩz_0 + h \in \Omega for all complex hh with h<r|h| < r, which prevents vacuous edge-cases). This is the first definition that is truly complex in nature. While this resembles the real definition of differentiability, note that hh is not real-valued, but rather h(CR2)h \in (\bC \cong \bR^2). We have made complex differentiability far more strict: this limit must exist not just when approaching from the left and right as in R\bR, but along any path, from every available angle, as h0h \to 0 in the complex plane. Of course, also note that the limit that defines f(z0)f'(z_0) is referred to as the (complex) derivative of ff at z0z_0.

[1.5.2]Theorem(Holomorphicity Implies Continuity)#

Suppose ff is holomorphic at some z0z_0 in ff's domain. Then ff is continuous at z0z_0.

Proof.

We show f(z0+h)f(z0)f(z_0 + h) \to f(z_0) as h0h \to 0 as such:

limh0f(z0+h)f(z0)=limh0(h×f(z0+h)f(z0)h)=0×f(z0)=0.\lim_{h \to 0} f(z_0 + h) - f(z_0) = \lim_{h \to 0} \left(h \times \frac{f(z_0 + h) - f(z_0)}{h}\right) = 0 \times f'(z_0) = 0.

Rearranging our definition of a complex derivative, we have that

limh0f(z0+h)f(z0)h=a    [f(z0+h)f(z0)]Δfah=o(h),\lim_{h \to 0} \frac{f(z_0 + h) - f(z_0)}{h} = a \implies \underbrace{[f(z_0 + h) - f(z_0)]}_{\Delta f} - ah = o(h),

where o(h)o(h) is some map such that limh0o(h)/h=0\lim_{h \to 0} o(h)/h = 0. This statement says that, for hCh \in \bC of small magnitude, we can approximate the deviation of ff from z0z_0 (denoted Δf=f(z0+h)f(z0)\Delta f = f(z_0 + h) - f(z_0)) very well with the linear change ahah. This approximation is so good that the error goes to zero much quicker than hh can go to 00. Note that limits (and thus derivatives) are unique, and so aa is the unique constant that approximates Δf\Delta f by the linear function ahah. In multivariate theory, we say that the linear map hahh \mapsto ah is the true derivative of ff, and this idea can be extended to all forms of finite-dimensional domains and codomains.

[1.5.3]Proposition(Basic Differentiation Rules for C\bC)#

Suppose f,gf, g are holomorphic functions on Ω\Omega.

  1. f+gf + g is holomorphic in Ω\Omega, with (f+g)=f+g(f + g)' = f' + g'.

  2. fgfg is holomorphic in Ω\Omega, with (fg)=fg+fg(fg)' = f'g + fg'.

  3. f/gf/g is holomorphic in Ω\Omega at points for which g0g \ne 0, with (f/g)=(fgfg)/g2(f/g)' = (f'g - fg')/g^2.

  4. The chain rule holds. For the two-function case f:ΩUf: \Omega \to U and g:UCg: U \to \bC, where both are holomorphic, we have that

    (gf)=g(f(z))f(z)zΩ.(g \circ f)' = g'(f(z))\,f'(z) \quad \forall z \in \Omega.

From this, we can prove basic results that polynomials, rational functions, and other nice classes of functions are holomorphic for suitable domains.